the above fraction can be written as 1 +   (10x-11)  

                                                         (x^2-8x+12)

   (10x-11)                                          ........................(1)

(x^2-8x+12)   

=   49/4             9/4      

       x-6              x-2

find the maximum and minimum values of (1) and thn add 1 to it..u'll get the range of the function

The 3-D polar coordinate system or the spherical coordinate system involves the distance from the origin and 2 angles

The position of point P is described as (r, phi ,theta  ),

where r = the distance from the origin (O),

phi  = the horizontal azimuth angle measured on the XY plane from the X axis in the counterclockwise direction,

theta  = the azimuth angle measured from the Z axis.

The relationship between the spherical coordinates and the Cartesian coordinates are

see, the incentre of a triangle is formed by the intersection of angle bisectors of the triangle.

for an isosceles triangle, thus the incentre will lie on the altitude of the triangle drawn from the 3rd angle, to the opposite side...

the othr conditions givvn in the question, will help u determine the exact location of the centre

for rest of the things, consult this book

books.google.co.in/books

i guess thr's a typo err out here :D....

so here's just  another way of solving the correct question  :)

three digit no. = a b c

for 1st digit, i.e. a, u have 5 choices

since repetition is allowed, same is for b and c

hence total no of ways = 5^3 = 125

just take an arbitrary point (h,k) which follows the required locus. then substitute thi spoint, in the given conditions for the locus, and eliminate any variable parameter.

finally,when u get an equation/relation in (h,k)... substitute, h=x and k=y

u hav the required locus !

         a_n = 10-3n

=> a_n+1 = 10-3n-3

now d = a_n+1 -a_n

           ₌  - 3

which is a constant value, independent of 'n'.

hence its an AP

any matrix A, with eigen values a_i is similar to its jordan form which is an upper triangular matrix

a1    b1   c1

0     a2    c2

0      0     a3

 and since similar matrices have same trace value, the trace of matrix A = sum of the eigen value

ur question is not clear... can u explain it a little more.

ofcourse dear....

see,if the common ratio is r, then b=ar and c=ar^2

thus 1/b = 1/ar  and 1/c=1/ar^2

hence they r also in gp, with common ratio 1/r ...

ofcourse dear....

see,if the common ratio is r, then b=ar and c=ar^2

thus 1/b = 1/ar  and 1/c=1/ar^2

hence they r also in gp, with common ratio 1/r ...

allaboutcircuits.com/vol_1/chpt_10/3.html

utwired.engr.utexas.edu/rgd1/lesson07.cfm

www.eas.asu.edu/~holbert/ece201/ECE201Lect-10.ppt

www.ibiblio.org/kuphaldt/socratic/output/dcmesh.pdf ----- Practice Problems

www.analyzethat.net/78_loop_circuit_analysis.php

powerelectrical.blogspot.com/

congrats sir ....u deserve it, undoubtedly :)

NIT Allahbad... it will giv u a better tagname !!!

Covalency is the number of electron pairs an atom can share with other atoms

u still hav gud chances to slide up.... however, even NIT-Ngp meta is not bad... infact its gud....so dnt worry even if u dnt get surathkal

gud luck

srry to say, bt u cant get admission in any of the NITs.